engine RPM divided by trans gear ratio divided by t-case ratio divided by axle ratio.
Example: 5000 rpm / 2.34 = 2137 2137 / 2 = 1068 1068 / 4.1 = 260 rpm. to convert to MPH, multiply tire diameter times pi roughly 3.14 equals inches travelled per revolution, so 42 x 3.14 = 131.88 x 260 rpm = 34288.88 inches per minute x 60 minutes per hour = 2,057,332.8 inches per hour divided by 12 inches per foot = 171444.4 feet per hour divided by 5280 feet per mile = 32.47 miles per hour WHEW Where trans gear ratio is 2.34 to one, t-case ratio is 2 to one and axle ratio is 4.10 to one. Now if there's an engineer out there, if you calculate final torque to the rear axle, in a locked axle, is the torque divided between the two wheels or is the full amount applied to each wheel? 200 lb/ft engine torque x 2.34 trans ratio = 468 lb/ft x 2.0 t-case ratio = 936 lb/ft x4.10 axle ratio = 3837.6 lb/ft. My question is this, is 3837 lb/ft applied to both wheels or is 1918.5 applied to each wheel?